P^4+10=14p^2

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Solution for P^4+10=14p^2 equation: 



^4+10=14P^2

We move all terms to the left:

^4+10-(14P^2)=0

We add all the numbers together, and all the variables

-14P^2=0

a = -14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-14)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$P=\frac{-b}{2a}=\frac{0}{-28}=0$

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